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Solutions for Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi 9780073401331

Solution for problem 19SE Chapter 4

A cereal manufacturer claims that the gross weight

Statistics for Engineers and Scientists | 4th Edition


Problem 19SE

A cereal manufacturer claims that the gross weight (including packaging) of a box of cereal labeled as weighing 12 oz has a mean of 12.2 oz and a standard deviation of 0.1 oz. You gather 75 boxes and weigh them all together. Let S denote the total weight of the 75 boxes of cereal.

a. If the claim is true, what is \(P(S \leq 914.8)\)?

b. Based on the answer to part (a), if the claim is true, is 914.8 oz an unusually small total weight for a sample of 75 boxes?

c. If the total weight of the boxes were 914.8 oz, would you be convinced that the claim was false? Explain.

d. If the claim is true, what is \(P(S \leq 910.3)\)?

e. Based on the answer to part (d), if the claim is true, is 910.3 oz an unusually small total weight for a sample of 75 boxes?

f. If the total weight of the boxes were 910.3 oz, would you be convinced that the claim was false? Explain.

Equation transcription:

Text transcription:

P(S \leq 914.8)

P(S \leq 910.3)

Accepted Solution
Step-by-Step Solution:

Solution

Step 1 of 7

Here we have to find the normal probabilities for the given conditions

The given mean

The given standard deviation is

Let S denote the weight of the 75 boxes

Then S is a normal variate with mean =75(12.2)

                                                                =915

                                  Standard deviation=0.1

                                                                =0.866


Chapter 4, Problem 19SE is Solved

Step 2 of 7


Step 3 of 7

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A cereal manufacturer claims that the gross weight