×
×

# The article "Assessment of Dermopharmacokinetic Approach ISBN: 9780073401331 38

## Solution for problem 2E Chapter 4.6

Statistics for Engineers and Scientists | 4th Edition

• Textbook Solutions
• 2901 Step-by-step solutions solved by professors and subject experts
• Get 24/7 help from StudySoup virtual teaching assistants Statistics for Engineers and Scientists | 4th Edition

4 5 0 376 Reviews
31
1
Problem 2E

The article "Assessment of Dermopharmacokinetic Approach in the Bioequivalence Determination of Topical Tretinoin Gel Products" (L. Pershing, J. Nelson, et al„ J Am Acad Dermatol 2003:740‒751) reports that the amount of a certain antifungal ointment that is absorbed into the skin can be modeled with a lognormal distribution. Assume that the amount (in ng/cm2) of active ingredient in the skin two hours after application is log normally distributed with μ = 2.2 and σ = 2.1.

a. Find the mean amount absorbed.

b. Find the median amount absorbed.

c. Find the probability that the amount absorbed is more than 100 ng/cm2.

d. Find the probability that the amount absorbed is less than 50 ng/cm2.

e. Find the 80th percentile of the amount absorbed.

f. Find the standard deviation of the amount absorbed.

Step-by-Step Solution:
Step 1 of 3

Solution 2E

Step1 of 7:

Let us consider a random variable X it presents the amount of active ingredient absorbed.

And X follows lognormal distribution with mean and standard deviation .

That is X N(2.2, 2.12)

Here our goal is:

a).We need to find the mean amount absorbed.

b).We need to find the median amount absorbed.

c).We need to find the probability that the amount absorbed is more than 100 ng/cm2.

d).We need to find the probability that the amount absorbed is less than 50 ng/cm2.

e).We need to find the 80th percentile of the amount absorbed.

f).We need to find the standard deviation of the amount absorbed.

Step2 of 7:

a).

The probability density function of lognormal distribution is given by Where, mean standard deviation

Z = standard normal variable.

Now, the mean amount absorbed is given by  = = = = 81.8591

Hence, E(X) = 81.8591

Step3 of 7:

b).

Here we need to find median of an amount of active ingredient absorbed. Let us consider “m” be the median lifetime of an electric component. And we know that median divides the data into two parts that is 0.5.

Now, median of the amount of active ingredient absorbed is given by  We know that X N(2.2, 2.12) Take   Hence, m = 9.0250.

Step4 of 7:

c).

The probability that the amount absorbed is more than 100 ng/cm2 is given by = = = = = = Here is obtained from statistical table(area under normal curve) (In...

Step 2 of 3

Step 3 of 3

##### ISBN: 9780073401331

Unlock Textbook Solution