A 0.145-kg baseball pitched horizontally at 32.0

Physics for Scientists & Engineers with Modern Physics | 4th Edition | ISBN: 9780131495081 | Authors: Douglas C. Giancoli

ISBN: 9780131495081 132

Solution for problem 9.6 Chapter 9

Physics for Scientists & Engineers with Modern Physics | 4th Edition

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Problem 9.6

A 0.145-kg baseball pitched horizontally at 32.0 m/sstrikes a bat and is popped straight up to a height of 36.5 m.If the contact time between bat and ball is 2.5 ms, calculatethe average force between the ball and bat during contact.

Step-by-Step Solution:

Step 1 of 3

**Workischangeintotalenergyamount. **Kindsofenergycanchangeevenifnoworkisdone. • GravitationalPotentialEnergy o Lifting/loweringthings;“height” o U =Gmgh § U G=(mass)(gravity)(height) § Example:Massof60kgliftedfromheight3mà4m.Beforeand afterGPE,howmuchwork 2 U Gi(60kg)(9.8m/s )(3m)=1764J 2 U Gf(60kg)(9.8m/s )(4m)=2352J W=U GfU =Gi88J • KineticEnergy“motion” 2 o K=½mv Example:Howmuchenergydoesa0.25kgballhaveat5m/s K=½mv =½(0.25kg)(5m/s) 2

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Chapter 9, Problem 9.6 is Solved

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Textbook: Physics for Scientists & Engineers with Modern Physics

Edition: 4

Author: Douglas C. Giancoli

ISBN: 9780131495081

This textbook survival guide was created for the textbook: Physics for Scientists & Engineers with Modern Physics, edition: 4. The answer to “A 0.145-kg baseball pitched horizontally at 32.0 m/sstrikes a bat and is popped straight up to a height of 36.5 m.If the contact time between bat and ball is 2.5 ms, calculatethe average force between the ball and bat during contact.” is broken down into a number of easy to follow steps, and 41 words. The full step-by-step solution to problem: 9.6 from chapter: 9 was answered by , our top Physics solution expert on 11/10/17, 05:57PM. This full solution covers the following key subjects: bat, contact, ball, Force, calculate. This expansive textbook survival guide covers 44 chapters, and 3904 solutions. Physics for Scientists & Engineers with Modern Physics was written by and is associated to the ISBN: 9780131495081. Since the solution to 9.6 from 9 chapter was answered, more than 286 students have viewed the full step-by-step answer.