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Oven thermostats were tested by setting them to 350°F and

Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi ISBN: 9780073401331 38

Solution for problem 8E Chapter 5.1

Statistics for Engineers and Scientists | 4th Edition

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Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi

Statistics for Engineers and Scientists | 4th Edition

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Problem 8E

Problem 8E

Oven thermostats were tested by setting them to 350°F and measuring the actual temperature of the oven. In a sample of 67 thermostats, the average temperature was 348.2°F and the standard deviation was 5.1°F.

a. Find a 90% confidence interval for the mean oven temperature.

b. Find a 95% confidence interval for the mean oven temperature.

c. What is the confidence level of the interval (347.5, 348.9)?

d. How many thermostats must be sampled so that a 90% confidence interval specifies the mean to within ±0.8°F?

e. How many thermostats must be sampled so that a 95% confidence interval specifies the mean to within ±0.8°F?

Step-by-Step Solution:
Step 1 of 3

Solution 8E

Step1 of 6:

Let us consider a random variable X it represents the oven temperature. Here random variable X follows normal distribution with mean standard deviation and n = 350.

That is

                       

The probability density function of normal distribution is given by

, .

Where,

x = random variable

= mean of X

= variance of X

= standard deviation os X

= mathematical constant and its value is 3.14

 

Here our goal is:

a. We need to find  90% confidence interval for the mean oven temperature.

b. We need to find 95% confidence interval for the mean oven temperature.

c. We need to find the confidence level of the interval (347.5, 348.9).

d. We need to check how many thermostats must be sampled so that a 90% confidence interval specifies the mean to within ±0.8°F.

e. We need to find how many thermostats must be sampled so that a 95% confidence interval specifies the mean to within ±0.8°F.


Step2 of 6:

a).

Here we have to find 90%  CI, let us take .

Now,

 

   = 0.05

Z-scores(are to the right) is given by

                                                                       

  is obtained from standard normal table(area under normal curve). In standard normal table we have to see where 0.9500 value falls, it falls in row 1.6 under column 0.04.

Hence,

90% confidence interval for the mean oven temperature is given by

   

     

         

(347.7529, 348.6470)

Hence,  90% confidence interval for the mean oven temperature is (347.7529, 348.6470).


Step3 of 6:

b).

Here we have to find 95%  CI, let us take .

Now,

 

   = 0.025

Z-scores(are to the right) is given by

                                                                       

  is obtained from standard normal table(area under normal curve). In standard normal table we have to see where 0.9750 value falls, it falls in row 1.9 under column 0.06.

Hence,

95% confidence interval for the mean oven temperature is given by

   

     

         

(347.6657, 348.7342)

Hence,  95% confidence interval for the mean oven temperature is (347.6657, 348.7342).


Step4 of 6:

c).

We have and n = 350.

In a given information we have upper bound 180

Now,

       

                   

348.9 - 348.2 = (0.2726)

                 0.7 =  (0.2726)

                                                =

   = 2.5678

Hence, = 2.56.

Z-scores is given by , and this value is obtained from standard normal table(area under normal curve). In standard normal table we have to see in row 2.5 under column 0.06.

 = 0.9948

Area to the right of Z is  1 - 0.9948

                                      = 0.0052.

Now,

             = 0.0104

Therefore level is (1-) = 1 - 0.0104

                                       = 0.9896.

Hence level is 0.9896.


Step5 of 6:

d).

We know that , s = 5.1 .

    = 0.8

= 0.8

       

     

               

                             

                              = 109.3070.

                             110

Hence, n = 110.


Step6 of 6:

e).

We know that , s = 5.1 .

    = 0.8

= 0.8

       

     

               

                     

                      = 156.1250.

                 157

Hence, n = 157.


Step 2 of 3

Chapter 5.1, Problem 8E is Solved
Step 3 of 3

Textbook: Statistics for Engineers and Scientists
Edition: 4
Author: William Navidi
ISBN: 9780073401331

Since the solution to 8E from 5.1 chapter was answered, more than 2167 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 8E from chapter: 5.1 was answered by , our top Statistics solution expert on 06/28/17, 11:15AM. This textbook survival guide was created for the textbook: Statistics for Engineers and Scientists , edition: 4. Statistics for Engineers and Scientists was written by and is associated to the ISBN: 9780073401331. The answer to “Oven thermostats were tested by setting them to 350°F and measuring the actual temperature of the oven. In a sample of 67 thermostats, the average temperature was 348.2°F and the standard deviation was 5.1°F.a. Find a 90% confidence interval for the mean oven temperature.________________b. Find a 95% confidence interval for the mean oven temperature.________________c. What is the confidence level of the interval (347.5, 348.9)?________________d. How many thermostats must be sampled so that a 90% confidence interval specifies the mean to within ±0.8°F?________________e. How many thermostats must be sampled so that a 95% confidence interval specifies the mean to within ±0.8°F?” is broken down into a number of easy to follow steps, and 100 words. This full solution covers the following key subjects: interval, confidence, oven, temperature, mean. This expansive textbook survival guide covers 153 chapters, and 2440 solutions.

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