In a sample of 80 ten-penny nails, the average weight was 1.56 g and the standard deviation was 0.1 g.

a. Find a 95% confidence interval for the mean weight of this type of nail.

b. Find a 98% confidence interval for the mean weight of this type of nail.

c. What is the confidence level of the interval (1.54, 1.58)?

d. How many nails must be sampled so that a 95%confidence interval specifies the mean to within ±0.01 d?

e. Approximately how many nails must be sampled so that a 98% confidence interval will specify the mean to within ±0.01 g?

Solution 9E

Step1 of 6:

Let us consider a random variable X it represents the weight of the penny nail. Here random variable X follows normal distribution with mean standard deviation and

n = 80.

That is

The probability density function of normal distribution is given by

, .

Where,

x = random variable

= mean of X

= variance of X

= standard deviation os X

= mathematical constant and its value is 3.14

Here our goal is:

a). We need to find 95% confidence interval for the mean weight of this type of nail.

b). We need to find 98% confidence interval for the mean weight of this type of nail.

c). We need to check what is the confidence level of the interval (1.54, 1.58)?

d). We need to find how many nails must be sampled so that a 95%confidence interval specifies the mean to within ±0.01 d.

e). We need to find how many nails must be sampled so that a 98% confidence interval will specify the mean to within ±0.01 g.

Step2 of 6:

a).

Here we have to find 95% CI, let us take .

Now,

= 0.025

Z-scores(are to the right) is given by

is obtained from standard normal table(area under normal curve). In standard normal table we have to see where 0.9750 value falls, it falls in row 1.9 under column 0.06.

Hence,

95% confidence interval for the mean weight of this type of nail is given by

(1.5380, 1.5819)

Hence, 95% confidence interval for the mean weight of this type of nail is (1.5380, 1.5819).

Step3 of 6:

b).

Here we have to find 98% CI, let us take .

Now,

= 0.01

Z-scores(are to the right) is given by

is obtained from standard normal table(area under normal curve). In standard normal table we have to see where 0.9900 value falls, it falls in row 2.3 under column 0.03.

Hence,

98% confidence interval for the mean weight of this type...