Problem 12.5
Calculate the forces FA and FB that the supports exerton the diving board of Fig. 12-49 when a 52-kg personstands at its tip. (a) Ignore the weight of the board, (b) Takeinto account the boards mass of 28 kg. Assumethe boards cg is at its center.
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**Workischangeintotalenergyamount. **Kindsofenergycanchangeevenifnoworkisdone. • GravitationalPotentialEnergy o Lifting/loweringthings;“height” o U =Gmgh § U G=(mass)(gravity)(height) § Example:Massof60kgliftedfromheight3mà4m.Beforeand afterGPE,howmuchwork 2 U Gi(60kg)(9.8m/s )(3m)=1764J 2 U Gf(60kg)(9.8m/s )(4m)=2352J W=U GfU =Gi88J • KineticEnergy“motion” 2 o K=½mv Example:Howmuchenergydoesa0.25kgballhaveat5m/s K=½mv =½(0.25kg)(5m/s) 2
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Chapter 12, Problem 12.5 is Solved
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