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A large box contains 10,000 ball bearings. A random sample
Chapter 5, Problem 23E(choose chapter or problem)
A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is , and the standard deviation is
. True or false:
a. A confidence interval for the mean diameter of the 120 bearings in the sample is \(10 \pm(1.96)(0.24) / \sqrt{120}\).
b. A confidence interval for the mean diameter of the 10,000 bearings in the box is
\(10 \pm(1.96)(0.24) / \sqrt{120}\).
c. A confidence interval for the mean diameter of the 10,000 bearings in the box is \(10 \pm(1.96)(0.24 / \sqrt{10,000}\)
Equation transcription:
Text transcription:
10 \pm(1.96)(0.24) / \sqrt{120}
10 \pm(1.96)(0.24 / \sqrt{10,000}
Questions & Answers
QUESTION:
A large box contains 10,000 ball bearings. A random sample of 120 is chosen. The sample mean diameter is , and the standard deviation is
. True or false:
a. A confidence interval for the mean diameter of the 120 bearings in the sample is \(10 \pm(1.96)(0.24) / \sqrt{120}\).
b. A confidence interval for the mean diameter of the 10,000 bearings in the box is
\(10 \pm(1.96)(0.24) / \sqrt{120}\).
c. A confidence interval for the mean diameter of the 10,000 bearings in the box is \(10 \pm(1.96)(0.24 / \sqrt{10,000}\)
Equation transcription:
Text transcription:
10 \pm(1.96)(0.24) / \sqrt{120}
10 \pm(1.96)(0.24 / \sqrt{10,000}
ANSWER:
Solution:
Step 1 of 2 :
A box contains 10,000 ball bearings. A random sample of 120 bearing is selected. The sample mean diameter is 10mm , and the standard deviation is 0.24 mm.
Here the population size is, N= 10,000
Sample size, n= 120.
Sample mean,
Standard deviation, = 0.24 mm.