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In a certain year, there were 80 days with measurable

Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi ISBN: 9780073401331 38

Solution for problem 11E Chapter 5.5

Statistics for Engineers and Scientists | 4th Edition

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Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi

Statistics for Engineers and Scientists | 4th Edition

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Problem 11E

In a certain year, there were 80 days with measurable snowfall in Denver, and 63 days with measurable snowfall in Chicago. A meteorologist computes (80 + 1)/(365 + 2) = 0.22, (63 + 1)/(365 + 2) = 0.17, and proposes to compute a 95% confidence interval for the difference between the proportions of snowy days in the two cities as follows:

                \(0.22-0.17 \pm 1.96 \sqrt{\frac{0.22)(0.78)}{367} \frac{(0.17)(0.83)}{367}}\)

Is this a valid confidence interval? Explain.

Equation transcription::

Text transcription:

0.22-0.17 \pm 1.96 \sqrt{\frac{0.22)(0.78)}{367} \frac{(0.17)(0.83)}{367}}

Step-by-Step Solution:
Step 1 of 3

Lecture 1: Statistics Info and some Basic Principles -­‐ Statistics is the most important science in the whole world: for upon it depends the practical application of every other science and of every art: the one science essential to all political and social administration, all education, all organization based on experience, for it only gives results of our experience." Florence Nightingale, Statistician -­‐ Statistics are numbers measured for some purpose. -­‐ Statistics is a collection of procedures and principles for gathering data and analyzing information in order to help people make decisions when faced with uncertainty. -­‐ Course Goal: Learn various tools for using data to gain understanding and make sound decisions about the world around us. -­‐ Chapter 1 starts out with eight statistical stories with morals, presented as seven case studies. -­‐ In each, data are used to make a decision, a judgment, about a situation. These case studies follow a wide range of ideas and methods and introduce a lot of statistical language. -­‐ 1. Who are those speedy drivers Principle: Simple summaries of data can tell an interesting story and are easier to digest than long lists. 2. Safety in the Skies Principle: When discussing the change in the rate or risk of occurrence of something, make sure you always include baseline or base rates. 3. Did anyone ask whom you’ve been dating Principle: A representative sample of only a few thousand, or perhaps even a few hundred, can give reasonably accurate information about a population of many millions. 4. Who are those angry women Principle: An unrepresentative sample, even a large one, tells you almost nothing about the population. 5. Does prayer lower blood pressure Principle: Cause-­‐and-­‐effect conclusions cannot generally be made on the basis of an observational study. 6. Does Aspirins reduce heart attack rates Principle: Unlike with observational studies, cause-­‐and effect conclusions can generally be made on the basis of randomized experiments. 7. Does the internet increase loneliness and depression Principle: A statistically significant finding does not necessarily have practical significance or importance. When a study reports a statistically significant finding, find out the magnitude of the relationship or difference. 8. Did your mother’s breakfast determine your sex Principle: For studies that found a relationship or difference, find out how many different things were tested. The more tests done, the more likely a statistically significant difference is a false positive that can be explained by chance. Watch out if many things are tested and only 1-­‐2 of them are statistically significant.

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Chapter 5.5, Problem 11E is Solved
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Textbook: Statistics for Engineers and Scientists
Edition: 4
Author: William Navidi
ISBN: 9780073401331

The answer to “?In a certain year, there were 80 days with measurable snowfall in Denver, and 63 days with measurable snowfall in Chicago. A meteorologist computes (80 + 1)/(365 + 2) = 0.22, (63 + 1)/(365 + 2) = 0.17, and proposes to compute a 95% confidence interval for the difference between the proportions of snowy days in the two cities as follows: \(0.22-0.17 \pm 1.96 \sqrt{\frac{0.22)(0.78)}{367} \frac{(0.17)(0.83)}{367}}\)Is this a valid confidence interval? Explain.Equation transcription::Text transcription:0.22-0.17 \pm 1.96 \sqrt{\frac{0.22)(0.78)}{367} \frac{(0.17)(0.83)}{367}}” is broken down into a number of easy to follow steps, and 78 words. Since the solution to 11E from 5.5 chapter was answered, more than 407 students have viewed the full step-by-step answer. This full solution covers the following key subjects: days, measurable, snowfall, interval, confidence. This expansive textbook survival guide covers 153 chapters, and 2440 solutions. The full step-by-step solution to problem: 11E from chapter: 5.5 was answered by , our top Statistics solution expert on 06/28/17, 11:15AM. This textbook survival guide was created for the textbook: Statistics for Engineers and Scientists , edition: 4. Statistics for Engineers and Scientists was written by and is associated to the ISBN: 9780073401331.

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In a certain year, there were 80 days with measurable