In Figure 9.21, the cg of the pole held by the pole vaulter is 2.00 m from the left hand, and the hands are 0.700 m apart. Calculate the force exerted by (a) his right hand and (b) his left hand. (c) If each hand supports half the weight of the pole in Figure 9.19, show that the second condition for equilibrium (net ? = 0) is satisfied for a pivot other than the one located at the center of gravity of the pole. Explicitly show how you follow the steps in the Problem-Solving Strategy for static equilibrium described above.
Solution 18PE Step-by-step solution Step 1 of 6 (a) Free body diagram of the left hand of a pole is: Step 2 of 6 The expression to find the weight is: Substitute for and for in the above expression, First condition of equilibrium: Here the pole is in equilibrium therefore, net force acting on the pole is zero. Here, left hand force, w is the weight of the pole and right hand force is . Step 3 of 6 Second condition of equilibrium: The pole is in equilibrium; therefore net torque about any point on the pole is zero. Take torque about the point through the force due to left hand acts, Substitute for in the above expression,