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A simple random sample consists of 65 lengths of piano
Chapter 6, Problem 2E(choose chapter or problem)
A simple random sample consists of 65 lengths of piano wire that were tested for the amount of extension under a load of 30 N. The average extension for the 65 lines was 1.102 mm and the standard deviation was 0.020 mm. Let \(\mu\) represent the mean extension for all specimens of this type of piano wire.
a. Find the P-value for testing \(H_{0}: \mu \leq 1.1\) versus \(H_{1}: \mu>1.1\).
b. Either the mean extension for this type of wire is greater than 1.1 mm, or the sample is in the most extreme __________ % of its distribution.
Equation Transcription:
Text Transcription:
mu
H_0: mu leq 1.1
H_1: mu > 1.1
Questions & Answers
QUESTION:
A simple random sample consists of 65 lengths of piano wire that were tested for the amount of extension under a load of 30 N. The average extension for the 65 lines was 1.102 mm and the standard deviation was 0.020 mm. Let \(\mu\) represent the mean extension for all specimens of this type of piano wire.
a. Find the P-value for testing \(H_{0}: \mu \leq 1.1\) versus \(H_{1}: \mu>1.1\).
b. Either the mean extension for this type of wire is greater than 1.1 mm, or the sample is in the most extreme __________ % of its distribution.
Equation Transcription:
Text Transcription:
mu
H_0: mu leq 1.1
H_1: mu > 1.1
ANSWER:Problem 2E
A simple random sample consists of 65 lengths of piano wire that were tested for the amount of extension under a load of 30 N. The average extension for the 65 lines was 1.102 mm and the standard deviation was 0.020 mm. Let µ represent the mean extension for all specimens of this type of piano wire.
a. Find the P-value for testing H0: ? 1.1 versus H1:µ > 1.1.
b. Either the mean extension for this type of wire is greater than 1.1 mm, or the sample is in the most extreme __________ % of its distribution.
Step by Step Solution
Step 1 of 3
Given,
Sample size,
Mean,
Standard deviation,
