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Solved: The two cylindrical rod segments are fixed to the

Mechanics of Materials | 10th Edition | ISBN: 9780134319650 | Authors: Russell C. Hibbeler ISBN: 9780134319650 134

Solution for problem 4-72 Chapter 4

Mechanics of Materials | 10th Edition

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Mechanics of Materials | 10th Edition | ISBN: 9780134319650 | Authors: Russell C. Hibbeler

Mechanics of Materials | 10th Edition

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Problem 4-72

The two cylindrical rod segments are fixed to the rigid walls such that there is a gap of 0.01 in. between them when T1 = 60F. Each rod has a diameter of 1.25 in. Determine the average normal stress in each rod if T2 = 400F, and also calculate the new length of the aluminum segment. Take aal = 13(10-6)>F, Eal = 10(103) ksi, (sY)al = 40 ksi, acu = 9.4(10-6)>F, (sY)cu = 50 ksi, and Ecu = 15(103) ksi.

Step-by-Step Solution:

Problem 4-72The two cylindrical rod segments are fixed to the rigid walls such that there is a gap of 0.01 in.between them when T = 60°F. Each rod has a diameter of 1.25 in. Determine the average 1normal stress in each rod if T = 400°F, an2 also calculate the new length of the aluminum -6 3 -6segment. Take a = 13(1al )/°F, E = 10(10 ) kal, (Y ) = 40 ksi, a al cu = 9.4(10 )/°F, (Y ) cu = 50 3ksi, and E cu= 15(10 ) ksi. Step-by-step solution Step 1 of 5 ^Draw the free body diagram of the cylindrical rod as following:\n

Step 2 of 5

Chapter 4, Problem 4-72 is Solved
Step 3 of 5

Textbook: Mechanics of Materials
Edition: 10
Author: Russell C. Hibbeler
ISBN: 9780134319650

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Solved: The two cylindrical rod segments are fixed to the