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Each day for 200 days,, a quality engineer samples 144

Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi ISBN: 9780073401331 38

Solution for problem 7E Chapter 6.14

Statistics for Engineers and Scientists | 4th Edition

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Statistics for Engineers and Scientists | 4th Edition | ISBN: 9780073401331 | Authors: William Navidi

Statistics for Engineers and Scientists | 4th Edition

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Problem 7E

Each day for 200 days,, a quality engineer samples 144 fuses rated at 15 A and measures the amperage at which they burn out. He performs a hypothesis test of H0:μ = 15 versus H1:μ≠ 15, where μ is the mean burn out amperage of the fuses manufactured that day.

a. On 10 of the 200 days,H0 is rejected at the 5% level. Does this provide conclusive evidence that the mean burnout amperage was different from 15 A on at least one of the 200 days? Explain.

b. Would the answer to part (a) be different ifH0 had been rejected on 20 of the 200 days? Explain.

Step-by-Step Solution:
Step 1 of 3

The Coefficient of Variation: C.V. = S / x(bar) X(bar)  Mean of data Examples: #1 X(bar)  54 ft S  26 ft C.V. = S / x(bar) = 26/54 = .48 or 48% #2 X(bar)  2 hours S  2.7 hours C.V. = 2.7 / 2 = 1.35 NOTICE: the units cancel when you divide the two numbers, therefore the answer does not have units!! Chebyster’s Theorem: For any set of numbers with mean x(bar) and standard...

Step 2 of 3

Chapter 6.14, Problem 7E is Solved
Step 3 of 3

Textbook: Statistics for Engineers and Scientists
Edition: 4
Author: William Navidi
ISBN: 9780073401331

The full step-by-step solution to problem: 7E from chapter: 6.14 was answered by , our top Statistics solution expert on 06/28/17, 11:15AM. Statistics for Engineers and Scientists was written by and is associated to the ISBN: 9780073401331. Since the solution to 7E from 6.14 chapter was answered, more than 236 students have viewed the full step-by-step answer. The answer to “Each day for 200 days,, a quality engineer samples 144 fuses rated at 15 A and measures the amperage at which they burn out. He performs a hypothesis test of H0:? = 15 versus H1:?? 15, where ? is the mean burn out amperage of the fuses manufactured that day.a. On 10 of the 200 days,H0 is rejected at the 5% level. Does this provide conclusive evidence that the mean burnout amperage was different from 15 A on at least one of the 200 days? Explain.________________b. Would the answer to part (a) be different ifH0 had been rejected on 20 of the 200 days? Explain.” is broken down into a number of easy to follow steps, and 105 words. This textbook survival guide was created for the textbook: Statistics for Engineers and Scientists , edition: 4. This full solution covers the following key subjects: days, amperage, mean, burn, rejected. This expansive textbook survival guide covers 153 chapters, and 2440 solutions.

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