Each day for 200 days,, a quality engineer samples 144 fuses rated at 15 A and measures the amperage at which they burn out. He performs a hypothesis test of H0:μ = 15 versus H1:μ≠ 15, where μ is the mean burn out amperage of the fuses manufactured that day.
a. On 10 of the 200 days,H0 is rejected at the 5% level. Does this provide conclusive evidence that the mean burnout amperage was different from 15 A on at least one of the 200 days? Explain.
b. Would the answer to part (a) be different ifH0 had been rejected on 20 of the 200 days? Explain.
The Coefficient of Variation: C.V. = S / x(bar) X(bar) Mean of data Examples: #1 X(bar) 54 ft S 26 ft C.V. = S / x(bar) = 26/54 = .48 or 48% #2 X(bar) 2 hours S 2.7 hours C.V. = 2.7 / 2 = 1.35 NOTICE: the units cancel when you divide the two numbers, therefore the answer does not have units!! Chebyster’s Theorem: For any set of numbers with mean x(bar) and standard...