CP Cavendish Experiment. ?In the Cavendish balance apparatus shown in Fig. 13.4, suppose that 25.0 kg and the rod connecting the pairs is 30.0 cm long. If, in each pair, are 12.0 cm apart center to center, find (a) the net force and (b) the net torque (about the rotation axis) on the rotating part of the apparatus. (c) Does it seem that the torque in part (b) would be enough to easily rotate the rod? Suggest some ways to improve the sensitivity of this experiment

Step 1 of 4 The gravity force between the spherically symmetric sphere is Gm 1 2 F =g r2 Step 2 of 4 6.67×1011×N.m /kg ×1.10 kg×25 kg 7 a)F =g (0.12 m) = 1.27 × 10 N The forces are in opposite direction so F net= 0