An object is moving with SHM of amplitude A on the end of a spring. If the amplitude is doubled, what happens to the total distance the object travels in one period? What happens to the period? What happens to the maximum speed of the object? Discuss how these answers are related.

Solution 1DQ Step 1: The equation for displacement of particle in simple harmonic motion is given by x = Acos(wt + ) Where A = Amplitude. Step 2: The displacement of a particle in simple harmonic motion is directly proportional to amplitude.the maximum displacement of the particle from its mean position is amplitude. The distance travelled from + A to A is 2A.time taken by the particle to travel 2A distance is half of the period.hence the particle will travel a total distance of 4A.