(I) A nylon string on a tennis racket is under a tension of 275 N. If its diameter is 1.00 mm, by how much is it lengthened from its untensioned length of 30.0 cm?
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T=275N (the tension in string)
d=1mm=1x10-3m (the diameter of the string)
L =0.30m (the original length of wire)
E=5x109N/m2 (young`s modulus of nylon)
A=π.r2 =3,14x(5x10-4)2=7.85x10-7 m2 (the cross-section area of the string)