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(I) A nylon string on a tennis racket is under a tension

Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli ISBN: 9780130606204 3

Solution for problem 38P Chapter 9

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 38P

(I) A nylon string on a tennis racket is under a tension of 275 N. If its diameter is 1.00 mm, by how much is it lengthened from its untensioned length of 30.0 cm?

Step-by-Step Solution:

Step-by-step solution

Step 1 of 2 ^

T=275N                    (the tension in string)

d=1mm=1x10-3m      (the diameter of the string)

r=d/2=0.5mm=0.5x10-3m=5x10-4m

L =0.30m                  (the original length of wire)

E=5x109N/m2                 (young`s modulus of nylon)

A=π.r2 =3,14x(5x10-4)2=7.85x10-7 m2  (the cross-section area of the string)

 

Step 2 of 2

Chapter 9, Problem 38P is Solved
Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780130606204

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