(I) A nylon string on a tennis racket is under a tension of 275 N. If its diameter is 1.00 mm, by how much is it lengthened from its untensioned length of 30.0 cm?

Step-by-step solution

Step 1 of 2 ^

T=275N (the tension in string)

d=1mm=1x10-3m (the diameter of the string)

r=d/2=0.5mm=0.5x10-3m=5x10-4m

L =0.30m (the original length of wire)

E=5x109N/m2 (young`s modulus of nylon)

A=π.r2 =3,14x(5x10-4)2=7.85x10-7 m2 (the cross-section area of the string)