An object is undergoing SHM with period 0.900 s and amplitude 0.320 m. At t = 0 the object is at x = 0.320 m and is instantaneously at rest. Calculate the time it takes the object to go (a) from x = 0.320 m to x = 0.160 m and (b) from x = 0.160 m to x = 0.

Solution to 9E Step 1 of 3 Introduction We need to find the time it takes to travel the given distance for an object undergoing SHM. Given, Time period of SHM =0.9s Amplitude =0.320m w=6.981rad/s Step 2 of 3 (a)X=0.320m to X=0.16m t1=0s The object is at X=0.16 at t2s Thus, t2=0.150s Time taken to move the distance t=t -t =(0.15-0)2 1 t2=0.15s