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Solved: A small block is attached to an ideal spring and
Chapter 14, Problem 14E(choose chapter or problem)
A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. When the amplitude of the motion is 0.090 m, it takes the block 2.70 s to travel from x = 0.090 m to x = - 0.090 m. If the amplitude is doubled, to 0.180 m, how long does it take the block to travel (a) from x = 0.180 m to x = - 0.180 m and (b) from x = 0.090 m to x = - 0.090 m?
Questions & Answers
QUESTION:
A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. When the amplitude of the motion is 0.090 m, it takes the block 2.70 s to travel from x = 0.090 m to x = - 0.090 m. If the amplitude is doubled, to 0.180 m, how long does it take the block to travel (a) from x = 0.180 m to x = - 0.180 m and (b) from x = 0.090 m to x = - 0.090 m?
ANSWER:Solution 14E Step 1 of 4: In the given problem when the small block is attached to ideal spring.When the amplitude is A=0.09 m it takes t=2.7s to travel from x=0.09m to x=-0.09m. Now when the amplitude is doubled, that is A=0.18 m, we need to calculate the time taken by the block to travel (a) From x= 0.180m to x= -0.180 m (b) From x= 0.09m to x= -0.09m