A 0.400-kg object undergoing SHM has ?ax = ?2.70 m when ?x = 0.300 m. What is the time for one oscillation?

Solution 16E Step 1: The equation for force exerted by a spring is F = kx (1) We know that net force F = ma Where mass of an object m = 0.450 kg Acceleration of the object a = 2.70 m/s2 2 F = (0.450 kg)( 2.70 m/s ) F = 1.125 N Step 2: Now we know the values of force and x then solve for force constant k. k = F/x k = 1.125 N/0.300 m k = 4.05 N/m