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# CP For the situation described in part (a) of Example ISBN: 9780321675460 31

## Solution for problem 29E Chapter 14

University Physics | 13th Edition

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Problem 29E

CP ?For the situation described in part (a) of Example 14.5, what should be the value of the putty mass ?m ?so that the amplitude after the collision is one-half the original amplitude? For this value of ?m?, what fraction of the original mechanical energy is converted into heat?

Step-by-Step Solution:

Solution 29E Step 1: a) the equation for the new amplitude, A 2 A 1 M+m Where, A - initial amplitude 1 M - Mass of the block m - Mass of the putty If, the new amplitude, A = A /2 2 1 Then, we can write, A1 M 2 = A1 M+m Cancel out the term A on both sides, 1 1 M 2 = M+m Squaring both sides, ¼ = M / (M+m) Or, (M+m) = 4M Or, m = 4M - M = 3M The mass of the putty should be, 3 times larger than that of the block

Step 2 of 2

##### ISBN: 9780321675460

The full step-by-step solution to problem: 29E from chapter: 14 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. Since the solution to 29E from 14 chapter was answered, more than 488 students have viewed the full step-by-step answer. This full solution covers the following key subjects: amplitude, original, heat, described, Energy. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The answer to “CP ?For the situation described in part (a) of Example 14.5, what should be the value of the putty mass ?m ?so that the amplitude after the collision is one-half the original amplitude? For this value of ?m?, what fraction of the original mechanical energy is converted into heat?” is broken down into a number of easy to follow steps, and 49 words. University Physics was written by and is associated to the ISBN: 9780321675460. This textbook survival guide was created for the textbook: University Physics, edition: 13.

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CP For the situation described in part (a) of Example