(II) At depths of 2000 m in the sea, the pressure is about 200 times atmospheric pressure (1 atm = 1.0 x 105 N/m2). By what percentage does the interior space of an iron bathysphere's volume change at this depth?

Step-by-step solution

Step 1 of 2 ^

Step-by-step solution

Step 1 of 3</p>

P0=1 atm = 1.0 x 105 N/m2 (the atmospheric pressure on the sea level. The bathyspehere is initially under this pressure)

P=200P0 (the pressure at 2000 m depth of the sea.)

ΔV (change in volume of the bathysphere when it is taken to 2000m deep)

B=90x109N/m2 (bulk modulus of iron)

V0 (initial volume of the bathysphere )

We are going to find the percentage change of volume of the bathysphere when it is taken from the surface of the sea to 2000m depth

Step 2 of 3</p>

Step 2 of 3</p>

The percentage change in volume

Minus sign shows the decrease in volume