Using Ionic Charge to Write Empirical Formulas for Ionic Compounds
Write the empirical formula of the compound formed by (a) AI3+ and Cl- ions, (b) AI3+ and O2- ions, (c) Mg2+ and NO-3 ions.
Write the empirical formula for the compound formed by (a) Na+ and PO43-, (b) Zn2+ and SO42-, (c) Fe3+ and CO32-.
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ACIDS AND BASES Acids: produces H+ (which is the same as protons and hydronium ion, H3O+) AND are mostly covalent compounds! H+ + OH- à H2O acid base neutralization The “protics” HCl à H+ Monoprotic ** Compounds that are monoprotic and H2SO 4à 2 H+ Diprotic diprotic are strong acids! H3PO 4à 3 H+ triprotic ** Triprotic are weak acids Ex: H2CO3 à Diprotic weak acid CH 3COOH à monoprotic weak acid Characteristics of acids: Sour Turns blue litmus paper into pink Strong Acids v. Weak acids : 2 converting pH concentration 3 Bases: substances producing OH- in an aqueous solutions AND are ALL ionic compounds Characteristics: Taste is unknown (no one has actuall
Textbook: Chemistry: The Central Science
Author: Theodore E. Brown; H. Eugene LeMay; Bruce E. Bursten; Catherine Murphy; Patrick Woodward; Matthew E. Stoltzfus
This full solution covers the following key subjects: Write, ions, empirical, compound, formed. This expansive textbook survival guide covers 305 chapters, and 6352 solutions. Chemistry: The Central Science was written by and is associated to the ISBN: 9780321910417. The full step-by-step solution to problem: 2PE from chapter: 2.10SE was answered by , our top Chemistry solution expert on 09/04/17, 09:30PM. This textbook survival guide was created for the textbook: Chemistry: The Central Science, edition: 13. The answer to “Using Ionic Charge to Write Empirical Formulas for Ionic CompoundsWrite the empirical formula of the compound formed by (a) AI3+ and Cl- ions, (b) AI3+ and O2- ions, (c) Mg2+ and NO-3 ions.Write the empirical formula for the compound formed by (a) Na+ and PO43-, (b) Zn2+ and SO42-, (c) Fe3+ and CO32-.” is broken down into a number of easy to follow steps, and 53 words. Since the solution to 2PE from 2.10SE chapter was answered, more than 243 students have viewed the full step-by-step answer.