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QUESTION:

Problem 1PE

Drawing Isomers

Draw all the structural and geometric isomers of pentene. C5H10. that have an unbranched hydrocarbon chain.

Which compound does not exist?

(a) 1,2.3.4.5.6.7-octaheptaene. (b) cis-2-butane. c) trans-3-hexene. (d) 1-propene. (e)cis-4-decene

Questions & Answers

QUESTION:

Problem 1PE

Drawing Isomers

Draw all the structural and geometric isomers of pentene. C5H10. that have an unbranched hydrocarbon chain.

Which compound does not exist?

(a) 1,2.3.4.5.6.7-octaheptaene. (b) cis-2-butane. c) trans-3-hexene. (d) 1-propene. (e)cis-4-decene

ANSWER:

Step 1 of 2

A compound having single bonds can rotate freely therefore there is no formation of cis, trans isomers. Similarly, a compound having double bond cannot rotate freely because they are fixed.

Therefore, double bonds can for cis, trans isomers thus, cis-2-butane has double bond and they cannot freely rotate and form two isomers.

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