Weighty Rope. ?If in Example 15.3 (Section 15.4) we do ?not ?neglect the weight of the rope, what is the wave speed (a) at the bottom of the rope; (b) at the middle of the rope; (c) at the top of the rope?
Solution 20E Step 1: In previous problem, provided, mass of the rope, mrope2.00 kg Mass of the box of rocks, mrock20 kg Length of the rope, L = 80 m Mass per unit length of the rope, m/L = = 2 kg / 80 m = 0.025 kg / m Step 2: a) At the bottom of the rope, the mass of the rope = L L = 80 m at bottom. Therefore, M = 0.025 kg / m × 80 m = 2 kg Tension on the rope, F = Total mass of the system × acceleration due to gravity Total mass of the system = mass of the rope + mass of the rock = 2 kg + 20 kg = 22 kg 2 Tension on the rope, F = (22 kg) × 9.8 m/s = 215.6 N Therefore, the equation for the speed of the wave, v = F Applying these values in the equation, we get, 215.6 N v = 0.025 kg/m v = 8624 m /s 2 Taking square root on both sides, we get, v = 92.87 m/s Speed of the wave at the bottom of the rope is, 92.87 m/s
Textbook: University Physics
Author: Hugh D. Young, Roger A. Freedman
Since the solution to 20E from 15 chapter was answered, more than 275 students have viewed the full step-by-step answer. The answer to “Weighty Rope. ?If in Example 15.3 (Section 15.4) we do ?not ?neglect the weight of the rope, what is the wave speed (a) at the bottom of the rope; (b) at the middle of the rope; (c) at the top of the rope?” is broken down into a number of easy to follow steps, and 43 words. This textbook survival guide was created for the textbook: University Physics, edition: 13. This full solution covers the following key subjects: rope, section, middle, neglect, bottom. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 20E from chapter: 15 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.