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A horizontal wire is stretched with a tension of 94.0 N,
Chapter 15, Problem 23E(choose chapter or problem)
A horizontal wire is stretched with a tension of 94.0 N, and the speed of transverse waves for the wire is 492 m/s. What must the amplitude of a traveling wave of frequency 69.0 Hz be m order for the average power carried by the wave to be 0.365 W?
Questions & Answers
QUESTION:
A horizontal wire is stretched with a tension of 94.0 N, and the speed of transverse waves for the wire is 492 m/s. What must the amplitude of a traveling wave of frequency 69.0 Hz be m order for the average power carried by the wave to be 0.365 W?
ANSWER:Solution 23E Step 1: Data given Tension T = 94.0 N Speed of waves v = 492 m/s Frequency f = 69.0 Hz Power P = 0.365 W We need to find the amplitude of traveling wave This is given by using 2 2 P = 1/2 (F A ) --------------(1) 2 We can obtain = T/v Substituting we get = 94.0 N/(492 m/s)2 = 3.89 × 104kg /m