Solution Found!

A horizontal wire is stretched with a tension of 94.0 N,

Chapter 15, Problem 23E

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

A horizontal wire is stretched with a tension of 94.0 N, and the speed of transverse waves for the wire is 492 m/s. What must the amplitude of a traveling wave of frequency 69.0 Hz be m order for the average power carried by the wave to be 0.365 W?

Questions & Answers

QUESTION:

A horizontal wire is stretched with a tension of 94.0 N, and the speed of transverse waves for the wire is 492 m/s. What must the amplitude of a traveling wave of frequency 69.0 Hz be m order for the average power carried by the wave to be 0.365 W?

ANSWER:

Solution 23E Step 1: Data given Tension T = 94.0 N Speed of waves v = 492 m/s Frequency f = 69.0 Hz Power P = 0.365 W We need to find the amplitude of traveling wave This is given by using 2 2 P = 1/2 (F A ) --------------(1) 2 We can obtain = T/v Substituting we get = 94.0 N/(492 m/s)2 = 3.89 × 104kg /m

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back