A horizontal wire is stretched with a tension of 94.0 N, and the speed of transverse waves for the wire is 492 m/s. What must the amplitude of a traveling wave of frequency 69.0 Hz be m order for the average power carried by the wave to be 0.365 W?

Solution 23E Step 1: Data given Tension T = 94.0 N Speed of waves v = 492 m/s Frequency f = 69.0 Hz Power P = 0.365 W We need to find the amplitude of traveling wave This is given by using 2 2 P = 1/2 (F A ) --------------(1) 2 We can obtain = T/v Substituting we get = 94.0 N/(492 m/s)2 = 3.89 × 104kg /m Step 2 : We can obtain angular velocity = 2 f Substituting we get = 2 × 69.0 Hz = 433.5 rad/s