Solution Found!
A wire with mass 40.0 g is stretched so that its ends are
Chapter 15, Problem 41E(choose chapter or problem)
A wire with mass 40.0 g is stretched so that its ends are tied down at points 80.0 cm apart. The wire vibrates in its fundamental mode with frequency 60.0 Hz and with an amplitude at the antinodes of 0.300 cm. (a) What is the speed of propagation of transverse waves in the wire? (b) Compute the tension in the wire. (c) Find the maximum transverse velocity and acceleration of particles in the wire.
Questions & Answers
QUESTION:
A wire with mass 40.0 g is stretched so that its ends are tied down at points 80.0 cm apart. The wire vibrates in its fundamental mode with frequency 60.0 Hz and with an amplitude at the antinodes of 0.300 cm. (a) What is the speed of propagation of transverse waves in the wire? (b) Compute the tension in the wire. (c) Find the maximum transverse velocity and acceleration of particles in the wire.
ANSWER:Solution to 41E Step 1 of 4 Introduction, The stretched wire vibrates with fundamental frequency of 60Hz, we are asked to find the wave velocity, the tension in the wire, and maximum transverse velocity and accelerations of particles in the wire, Given, -3 Mass of the wire=40g = 40x10 kg Length of the wire =0.8m Frequency of vibration=60Hz Amplitude at anti node =0.3cm