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A 1750-N irregular beam is hanging horizontally by its

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 54P Chapter 15

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 54P

A 1750-N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (?A and ?B?), each 1.25 m long and weighing 0.360 N. The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached. If you pluck both strings at the same time at the beam, what is the time delay between the arrival of the two pulses at the ceiling? Which pulse arrives first? (Neglect the effect of the weight of the wires on the tension in the wires.)

Step-by-Step Solution:

Solution 54P Step 1 of 6: The total force F= 1750 N is due to the sum of tension in wires A and B. F=T + T =1750 N a b Length of wire, L= 1.25 Weight, W=0.360 N Using W= mg mass m=(W/g) m=(0.360/9.8) m=0.0367 kg Step 2 of 6: In order to calculate the time delay between two pulses of reaching ceiling , we need to calculate the tension and speed on two wires A and B. To calculate the tension, If we sum moments about one end, we can find the tension at the other. For A, 1750 (3)=T Lb T = 1750 b 3 T = 583.33 N b Similarly for B, Using =T + T =1750 N a b T =1750 N-T a b T =1750 N- 583.33 N a T =1166.67 N a Step 3 of 6: To calculate the speed, For a wire with tension T and mass per unit length , the speed of the wave is given by v = T m Using = L Substituting m=0.0367 kg and L= 1.25 m 0.0367 kg = 1.25 m =0.2936 kg/m Using in speed equation, v = 0.2936 kg/m...1

Step 4 of 6

Chapter 15, Problem 54P is Solved
Step 5 of 6

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

University Physics was written by and is associated to the ISBN: 9780321675460. This full solution covers the following key subjects: beam, wires, ceiling, irregular, arrives. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. Since the solution to 54P from 15 chapter was answered, more than 565 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 54P from chapter: 15 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. The answer to “A 1750-N irregular beam is hanging horizontally by its ends from the ceiling by two vertical wires (?A and ?B?), each 1.25 m long and weighing 0.360 N. The center of gravity of this beam is one-third of the way along the beam from the end where wire A is attached. If you pluck both strings at the same time at the beam, what is the time delay between the arrival of the two pulses at the ceiling? Which pulse arrives first? (Neglect the effect of the weight of the wires on the tension in the wires.)” is broken down into a number of easy to follow steps, and 97 words. This textbook survival guide was created for the textbook: University Physics, edition: 13.

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