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For a string stretched between two supports, two
Chapter 15, Problem 15.61(choose chapter or problem)
For a string stretched between two supports, two successive standing-wave frequencies are 525 Hz and 630 Hz. There are other standing-wave frequencies lower than 525 Hz and higher than 630 Hz. If the speed of transverse waves on the string is 384 m/s, what is the length of the string? Assume that the mass of the wire is small enough for its effect on the tension in the wire to be neglected.
Questions & Answers
QUESTION:
For a string stretched between two supports, two successive standing-wave frequencies are 525 Hz and 630 Hz. There are other standing-wave frequencies lower than 525 Hz and higher than 630 Hz. If the speed of transverse waves on the string is 384 m/s, what is the length of the string? Assume that the mass of the wire is small enough for its effect on the tension in the wire to be neglected.
ANSWER:Step 1 of 3
The frequency of nth harmonic of a standing wave is given by \(f_{n}=n \frac{v}{2 L}\), where v is the speed of the wave, and L is the length of the string.
Given that, the frequency of a certain harmonic, say x is \(f_{x}=x \frac{v}{2 L}=x f_{1},\), where \(f_{1}\) is the fundamental frequency, \(f_{1}=\frac{v}{2 L}\)