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# For a string stretched between two supports, two

ISBN: 9780321675460 31

## Solution for problem 61P Chapter 15

University Physics | 13th Edition

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University Physics | 13th Edition

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Problem 61P

For a string stretched between two supports, two successive standing-wave frequencies are 525 Hz and 630 Hz. There are other standing-wave frequencies lower than 525 Hz and higher than 630 Hz. If the speed of transverse waves on the string is 384 m/s, what is the length of the string? Assume that the mass of the wire is small enough for its effect on the tension in the wire to be ignored.

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Solution 61P The frequency of n th harmonic of a standing wave is given by f = n v , where v is the n 2L speed of the wave, and L is the length of the string. Given that, the frequency of a certain harmonic, say x is f = x x v = xf , where f is 2L 1 1 the fundamental frequency, f = v 1 2L 525 Hz = xf …1.(1) Frequency of the next harmonic,...

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##### ISBN: 9780321675460

University Physics was written by and is associated to the ISBN: 9780321675460. Since the solution to 61P from 15 chapter was answered, more than 296 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: University Physics, edition: 13. The answer to “For a string stretched between two supports, two successive standing-wave frequencies are 525 Hz and 630 Hz. There are other standing-wave frequencies lower than 525 Hz and higher than 630 Hz. If the speed of transverse waves on the string is 384 m/s, what is the length of the string? Assume that the mass of the wire is small enough for its effect on the tension in the wire to be ignored.” is broken down into a number of easy to follow steps, and 72 words. This full solution covers the following key subjects: string, Wire, wave, Frequencies, standing. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The full step-by-step solution to problem: 61P from chapter: 15 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

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