For a string stretched between two supports, two successive standing-wave frequencies are 525 Hz and 630 Hz. There are other standing-wave frequencies lower than 525 Hz and higher than 630 Hz. If the speed of transverse waves on the string is 384 m/s, what is the length of the string? Assume that the mass of the wire is small enough for its effect on the tension in the wire to be ignored.

Solution 61P The frequency of n th harmonic of a standing wave is given by f = n v , where v is the n 2L speed of the wave, and L is the length of the string. Given that, the frequency of a certain harmonic, say x is f = x x v = xf , where f is 2L 1 1 the fundamental frequency, f = v 1 2L 525 Hz = xf …1.(1) Frequency of the next harmonic,...