Does the sound intensity level ? obey the inverse-square law? Why?

Solution 11DQ Step 1 The sound intensity level is given by I = log( )I 0 Where I is0the reference intensity. Now let us consider a sound source releasing sound at an power P , hence the intensity of the sound at a distance r is I = r2 Now putting this value on the equation of intensity level we have 2 = log( P/r ) = 2log( P ) I0 I0r So we can see that the intensity level of sound decreases as log( ). 1 r So sound intensity level does not obey the inverse square law.