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Get Full Access to University Physics - 13 Edition - Chapter 16 - Problem 16e
Get Full Access to University Physics - 13 Edition - Chapter 16 - Problem 16e

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# Unless indicated otherwise, assume the speed of | Ch 16 - 16E

ISBN: 9780321675460 31

## Solution for problem 16E Chapter 16

University Physics | 13th Edition

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University Physics | 13th Edition

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Problem 16E

Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. BIO Human Hearing. A fan at a rock concert is 30 m from the stage, and at this point the sound intensity level is 110 dB. (a) How much energy is transferred to her eardrums each second? (b) How fast would a 2.0-mg mosquito have to fly (in mm/s) to have this much kinetic energy? Compare the mosquito’s speed with that found for the whisper in part (a) of Exercise 16.13. 16.13 .. ?BIO Energy Delivered to the Ear. Sound is detected when a sound wave causes the tympanic membrane (the eardrum) to vibrate. Typically, the diameter of this membrane is about 8.4 mm in humans. (a) How much energy is delivered to the eardrum each second when someone whispers (20 dB) a secret in your ear? (b) To comprehend how sensitive the ear is to very small amounts of energy, calculate how fast a typical 2.0-mg mosquito would have to fly (in mm/s) to have this amount of kinetic energy.

Step-by-Step Solution:

Solution 16E Step 1 of 3: We know that I = 1 × 1010w m 2 2 The area of the tympanic membrane is A = r 3 r = 4.2 × 10 m and = 3.14 A = 3.14 × (4.2 × 10 ) = 55.39 × 10 m6 2 Step 2 of 3: a)Intensity is the energy per unit area per unit time E I = At We have to find energy so E = IAt =1 × 10 10 × 55.39 × 10 6× 1 =5.539 × 10 1J Step 3 of 3: b)The energy possessed by the object by virtue of its motion is called kinetic energy 1 2 K.E = m2 v = 2 K.E m = 2×5.5×1015 2×106 5 =7.4 × 10 m/s = 0.074 mm/s Step 1 of 3: We know that = 10 dB log( ) I0 The area of the eardrum is A = r 2 3 r = 4.2 × 10 m v = 0.074 mm A = 3.14 × 4.2 × 103 =55.39 × 10 m6 2 Step 2 of 3: a) = 110 dB I = 11 log (I0 I = 10 I = 0.1 w/m 2 0 Intensity is energy per unit area per unit time I = E At We have to find energy so E = IAt 6 =0.1 × 55.39 × 10 × 1 6 = 5.5 × 10 J

Step 3 of 3

##### ISBN: 9780321675460

This textbook survival guide was created for the textbook: University Physics, edition: 13. Since the solution to 16E from 16 chapter was answered, more than 420 students have viewed the full step-by-step answer. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 16E from chapter: 16 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. The answer to “Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. BIO Human Hearing. A fan at a rock concert is 30 m from the stage, and at this point the sound intensity level is 110 dB. (a) How much energy is transferred to her eardrums each second? (b) How fast would a 2.0-mg mosquito have to fly (in mm/s) to have this much kinetic energy? Compare the mosquito’s speed with that found for the whisper in part (a) of Exercise 16.13. 16.13 .. ?BIO Energy Delivered to the Ear. Sound is detected when a sound wave causes the tympanic membrane (the eardrum) to vibrate. Typically, the diameter of this membrane is about 8.4 mm in humans. (a) How much energy is delivered to the eardrum each second when someone whispers (20 dB) a secret in your ear? (b) To comprehend how sensitive the ear is to very small amounts of energy, calculate how fast a typical 2.0-mg mosquito would have to fly (in mm/s) to have this amount of kinetic energy.” is broken down into a number of easy to follow steps, and 177 words. This full solution covers the following key subjects: Energy, Sound, EAR, much, mosquito. This expansive textbook survival guide covers 26 chapters, and 2929 solutions.

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