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Two identical taut strings under the same tension F

Chapter 16, Problem 57P

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QUESTION:

Two identical taut strings under the same tension ?F produce a note of the same fundamental frequency ?f?0. The tension in one of them is now increased by a very small amount ??F?. (a) If they are played together in their fundamental, show that the frequency of the beat produced is ?f?beat = ?f?0 (??F?/2?F?). (b) Two identical violin Strings, when in tune and stretched with the same tension, have a fundamental frequency of 440.0 Hz. one of the strings is retuned by increasing its tension. When this is done, 1.5 beats per second are heard when both strings are plucked simultaneously at their centers. By what percentage was the string tension changed?

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QUESTION:

Two identical taut strings under the same tension ?F produce a note of the same fundamental frequency ?f?0. The tension in one of them is now increased by a very small amount ??F?. (a) If they are played together in their fundamental, show that the frequency of the beat produced is ?f?beat = ?f?0 (??F?/2?F?). (b) Two identical violin Strings, when in tune and stretched with the same tension, have a fundamental frequency of 440.0 Hz. one of the strings is retuned by increasing its tension. When this is done, 1.5 beats per second are heard when both strings are plucked simultaneously at their centers. By what percentage was the string tension changed?

ANSWER:

Solution 57P Step 1 The frequency of a string, f F Where, F - tension on the string The equation for the fundamental frequency, f F 0 0 Consider the tension has slightly increased. Then, the new frequency, f ’ F Dividing both these equations. f0/f ’ = F 0 / F

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