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Two identical taut strings under the same tension F

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 57P Chapter 16

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 57P

Two identical taut strings under the same tension ?F produce a note of the same fundamental frequency ?f?0. The tension in one of them is now increased by a very small amount ??F?. (a) If they are played together in their fundamental, show that the frequency of the beat produced is ?f?beat = ?f?0 (??F?/2?F?). (b) Two identical violin Strings, when in tune and stretched with the same tension, have a fundamental frequency of 440.0 Hz. one of the strings is retuned by increasing its tension. When this is done, 1.5 beats per second are heard when both strings are plucked simultaneously at their centers. By what percentage was the string tension changed?

Step-by-Step Solution:

Solution 57P Step 1 The frequency of a string, f F Where, F - tension on the string The equation for the fundamental frequency, f F 0 0 Consider the tension has slightly increased. Then, the new frequency, f ’ F Dividing both these equations. f0/f ’ = F 0 / F

Step 2 of 3

Chapter 16, Problem 57P is Solved
Step 3 of 3

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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Two identical taut strings under the same tension F