BIO Temperatures in Biomedicine. (a) Normal body temperature. The average normal body temperature measured in the mouth is 310 K. What would Celsius and Fahrenheit thermometers read for this temperature? (b) ?Elevated body temperature. During very vigorous exercise, the body’s temperature can go as high as 40o C. What would Kelvin and Fahrenheit thermometers read for this temperature? (c) ?Temperature difference in the body. The surface temperature of the body is normally about 7 Co lower than the internal temperature. Express this temperature difference in kelvins and in Fahrenheit degrees. (d) Blood storage. Blood stored at 4.0o C lasts safely for about 3 weeks, whereas blood stored at – 160o C lasts for 5 years. Express both temperatures on the Fahrenheit and Kelvin scales. (e) Heat stroke. If the body’s temperature is above 105o F for a prolonged period, heat stroke can result. Express this temperature on the Celsius and Kelvin scales.
Solution 2E BIO Temperatures in Biomedicine Problem (a) Step 1: Temperature of mouth T = 310K K To find it in °C and °F T = T - 273.15 C K T C = 310-273.15 T C = 36.85°C Step 2: In °F T F = 1.8(T C+ 32 T F = 1.8*36.85 + 32 T F = 98.33°F Celsius and Fahrenheit thermometers will read the temperatures as 36.85°C and 98.33°F Elevated body temperature Problem (b) Step 1: Body temperature after exercise in celsiTsC = 40°C Step 2: In K T K = C + 273.15 T K = 40+273.15 T K = 313.15K Step 3: In F T F = 1.8(T C+ 32 T F = 1.8*40+ 32 T F = 40°F Temperature difference in body Problem (c) Step 1: Difference in surface temp to body temp = 7°C In K T = T + 273.15 K C T = 7+273.15 K T K = 280.15.5K Step 2: In F T F = 1.8(T C+ 32 T F = 1.8*7+ 32 T F = 44.6°F Blood Storage Problem (d) Step 1: (i)For 3 weeks T C = 4°C Step 2: (i)In K T K = T C + 273.15 T K = 4+273.15 T K = 277.15.5K Step 3: In F T F = 1.8(T C+ 32 T F = 1.8*4+ 32 T F = 39.2°F Step 4: (ii)For 5 years T C = 160°C In K T K = T C + 273.15 T K = 160+273.15 T K = 433.15K Step 5: In F T F = 1.8(T C+ 32 T F = 1.8*160+ 32 T F = 320°F Heat Stroke Step 1: Heat stroke happens at prolonged exposure to heat in 105°F Step 2: To convert it to C and F Scale In C T = (T -32)x5 C F 9 T = (105 - 32)*0.556 C T = 40.56°C C