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Air enters the diffuser of a ramjet engine (Fig. 9.27c) at

Fundamentals of Engineering Thermodynamics | 8th Edition | ISBN: 9781118412930 | Authors: Michael J. Moran ISBN: 9781118412930 139

Solution for problem 9.90 Chapter 9

Fundamentals of Engineering Thermodynamics | 8th Edition

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Fundamentals of Engineering Thermodynamics | 8th Edition | ISBN: 9781118412930 | Authors: Michael J. Moran

Fundamentals of Engineering Thermodynamics | 8th Edition

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Problem 9.90

Air enters the diffuser of a ramjet engine (Fig. 9.27c) at 6 lbf/in.2 , 4208R, with a velocity of 1600 ft/s, and decelerates essentially to zero velocity. After combustion, the gases reach a temperature of 22008R before being discharged through the nozzle at 6 lbf/in.2 On the basis of an airstandard analysis, determine (a) the pressure at the diffuser exit, in lbf/in.2 (b) the velocity at the nozzle exit, in ft/s. Neglect kinetic energy except at the diffuser inlet and the nozzle exit. Assume combustion occurs at constant pressure and flow through the diffuser and nozzle is isentropic.

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• SpeedingUpIndex o Somethingpersomethingelse=index o something/somethingelse=speed/time=acceleration • Tofindacceleration…(twoways) 1. DataTableWay Example: t v Δt(t 2t 1) Δv(v 2v )1 a(Δv/Δt) 0s 5mph -- -- -- 2s 25mph 2 20 10 4s 45mph 2 20 10 2. AccelerationEquation:(a)=Δv/Δt (0s,5mph) (4s,45mph) a=Δv/Δt=(45mph-5mph)/(4s-0s)=40mph/4s=10mph/s v=

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Chapter 9, Problem 9.90 is Solved
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Textbook: Fundamentals of Engineering Thermodynamics
Edition: 8
Author: Michael J. Moran
ISBN: 9781118412930

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Air enters the diffuser of a ramjet engine (Fig. 9.27c) at