The outer diameter of a glass jar and the inner diameter of its iron lid are both 725 mm at r??m temperature (20.0°C). What will be the size of the difference in these diameters if the lid is briefly held under hot water until its temperature rises to 50.0°C, without changing the temperature of the glass?
CHEM 112 Notes (12016) Solubility and Temperature: Solubility of gas—think in terms of pressure o Solubility of gas A = partial pressure of gas A (P A o ↑P , ↑Aolubility A o ↓P , ↓Aolubility A Biggest factor in solubility = ΔH (change in enthalpy) o If we have +ΔH (endothermic), heat = reactant (A + B + heat → C) Increase heat, increase solubility (shoving heat towards product) (↑heat, ↑solubility) o If we have –ΔH(exothermic), heat = product (A + B → C + heat) Increase heat, decrease solubility (↑heat, ↓solubility) As we increase temperature, solubility increases (in general)—exothermic is exception Colligative Properties: Rely/depend on the concentration of the solute Add solute—lowers vapor pressure (changing the equilibrium of solution) If we have a pure solvent, we have equilibrium o # molecules evaporating = # molecules condensing Pure Add solute solvent Molecules evaporating Molecules evaporating = = Molecules condensing Molecules condensing Rauoult’s Law: o Vapor pressure solvents propotional tχ solvent o To find new vapor pressure:
