Solution Found!
A 4-lb mass of oxygen (O2) is mixed with 8 lb of another
Chapter 12, Problem 12.6(choose chapter or problem)
A 4-lb mass of oxygen (\(\mathrm{O}_{2}\)) is mixed with 8 lb of another gas to form a mixture that occupies \(45 \mathrm{ft}^{3}\) at \(150^{\circ} \mathrm{F}\), \(40 \mathrm{lbf} / \mathrm{in}^{2}\) Applying ideal gas mixture principles, determine
(a) the molecular weight of the unspecified gas.
(b) the analysis of the mixture in terms of mole fractions.
Questions & Answers
QUESTION:
A 4-lb mass of oxygen (\(\mathrm{O}_{2}\)) is mixed with 8 lb of another gas to form a mixture that occupies \(45 \mathrm{ft}^{3}\) at \(150^{\circ} \mathrm{F}\), \(40 \mathrm{lbf} / \mathrm{in}^{2}\) Applying ideal gas mixture principles, determine
(a) the molecular weight of the unspecified gas.
(b) the analysis of the mixture in terms of mole fractions.
ANSWER:Step 1 of 3
Known:
Four lb of 
We need to determine the molecular weight of the unspecified gas and the molar analysis of the mixture.
Schematic and given data
We assume that
(1) The overall mixture acts as an ideal gas.
(2) Each mixture component behaves as if it were an ideal gas occupying the entire volume at the mixture temperature.