You are given a sample of metal and asked to determine its specific heat. You weigh the sample and find that its weight is 28.4 N. You carefully add 1.25 X 104 J of heat energy to the sample and find that its temperature rises 18.0 Co. What is the sample’s specific heat?

Solution 29E Introduction The energy supplied to increase the temperature of an object is given by Q = mcT c = Q mT Step 1 The weight of the metal is w = mg = 28.4 N Hence the mass of the metal is m =w = 28.4 N= 2.898 kg g 9.8 m/s 4 The supplied energy is Q = 1.25 × 10 J . And the change in the temperature is T = 18.0°C = 18.0 K