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Get Full Access to University Physics - 13 Edition - Chapter 17 - Problem 54e
Get Full Access to University Physics - 13 Edition - Chapter 17 - Problem 54e

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# BIO Evaporation of sweat is an important mechanism for

ISBN: 9780321675460 31

## Solution for problem 54E Chapter 17

University Physics | 13th Edition

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Problem 54E

BIO Evaporation of sweat is an important mechanism for temperature control in some warm-blooded animals. (a) What mass of water must evaporate from the skin of a 70.0-kg man to cool his body 1.00 C? ? The heat of vaporization of water at body temperature (37? C) is 2.42 X 10? J/kg. The specific heat of a typical human body is 3480 J/kg ? K (see Exercise 17.25). (b) What volume of water must the man drink to replenish the evaporated water? Compare to the volume of a soft-drink can (355 m? ). 3? 17.25 . ?BIO While running, a 70-kg student generates thermal energy at a rate of 1200 W. For the runner to maintain a constant body temperature of 37o C, this energy must be removed by perspiration or other mechanisms. If these mechanisms failed and the energy could not flow out of the student’s body, for what amount of time could a student run before irreversible body damage occurred? (?Note?: Protein structures in the body are irreversibly damaged if body temperature rises to 44o C or higher. The specific heat of a typical human body is 3480 J/kg ? K, slightly less than that of water. The difference is due to the presence of protein, fat, and minerals, which have lower specific heats.)

Step-by-Step Solution:
Step 1 of 3

Solution 54E Step1 : In this question , we need to find Mass the of water that has to evaporated to reduce temperature by 1.0 C 0 Volume of water that a man should drink to replenish the evaporated the water Data given Mass of person m = 75 kg Heat generated by the person Q = 2.42 × 10 J/kg6 Specific heat of person c = 3480 J/Kg p 0 0 0 Change in temperature T = 37 C 1 C = 36 C

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