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Show that Cx = B 1Dt expa - x2 4Dt b is also a solution to

Materials Science and Engineering: An Introduction | 9th Edition | ISBN: 9781118324578 | Authors: William Callister ISBN: 9781118324578 140

Solution for problem 5.12 Chapter 5

Materials Science and Engineering: An Introduction | 9th Edition

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Materials Science and Engineering: An Introduction | 9th Edition | ISBN: 9781118324578 | Authors: William Callister

Materials Science and Engineering: An Introduction | 9th Edition

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Problem 5.12

Show that Cx = B 1Dt expa - x2 4Dt b is also a solution to Equation 5.4b. The parameter B is a constant, being independent of both x and t. Hint: From Equation 5.4b, demonstrate that 0c B 1Dt expa - x2 4Dt b d 0t is equal to D 0 2 c B 1Dt expa - x2 4Dt b d 0x2

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Chapter 5, Problem 5.12 is Solved
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Textbook: Materials Science and Engineering: An Introduction
Edition: 9
Author: William Callister
ISBN: 9781118324578

This textbook survival guide was created for the textbook: Materials Science and Engineering: An Introduction, edition: 9. The answer to “Show that Cx = B 1Dt expa - x2 4Dt b is also a solution to Equation 5.4b. The parameter B is a constant, being independent of both x and t. Hint: From Equation 5.4b, demonstrate that 0c B 1Dt expa - x2 4Dt b d 0t is equal to D 0 2 c B 1Dt expa - x2 4Dt b d 0x2” is broken down into a number of easy to follow steps, and 63 words. Since the solution to 5.12 from 5 chapter was answered, more than 522 students have viewed the full step-by-step answer. This full solution covers the following key subjects: expa, equation, also, constant, demonstrate. This expansive textbook survival guide covers 22 chapters, and 1041 solutions. Materials Science and Engineering: An Introduction was written by and is associated to the ISBN: 9781118324578. The full step-by-step solution to problem: 5.12 from chapter: 5 was answered by , our top Engineering and Tech solution expert on 11/14/17, 08:41PM.

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