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Materials Science and Engineering: An Introduction | 9th Edition | ISBN: 9781118324578 | Authors: William Callister
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A cylindrical rod of steel (E = 207 GPa, 30 * 106 psi)

Chapter 6, Problem 6.8

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QUESTION:

A cylindrical rod of steel (E = 207 GPa, 30 * 106 psi) having a yield strength of 310 MPa (45,000 psi) is to be subjected to a load of 11,100 N (2500 lbf). If the length of the rod is 500 mm (20.0 in.), what must be the diameter to allow an elongation of 0.38 mm (0.015 in.)?

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QUESTION:

A cylindrical rod of steel (E = 207 GPa, 30 * 106 psi) having a yield strength of 310 MPa (45,000 psi) is to be subjected to a load of 11,100 N (2500 lbf). If the length of the rod is 500 mm (20.0 in.), what must be the diameter to allow an elongation of 0.38 mm (0.015 in.)?

ANSWER:

Problem 6.8

A cylindrical rod of steel (E = 207 GPa, 30 * 106 psi) having a yield strength of 310 MPa (45,000 psi) is to be subjected to a load of 11,100 N (2500 lbf). If the length of the rod is 500 mm (20.0 in.), what must be the diameter to allow an elongation of 0.38 mm (0.015 in.)?

                                                              Step by Step Solution

Step 1 of 3

We are given rod steel under stress  where the applied force is  and causes an elongation .The initial length  of the alloy is

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