A cylindrical specimen of stainless steel having a diameter of 12.8 mm (0.505 in.) and a gauge length of 50.800 mm (2.000 in.) is pulled in tension. Use the loadelongation characteristics shown in the following table to complete parts (a) through (f). Load Length N lbf mm in. 0 0 50.800 2.000 12,700 2,850 50.825 2.001 25,400 5,710 50.851 2.002 38,100 8,560 50.876 2.003 50,800 11,400 50.902 2.004 76,200 17,100 50.952 2.006 89,100 20,000 51.003 2.008 92,700 20,800 51.054 2.010 102,500 23,000 51.181 2.015 107,800 24,200 51.308 2.020 119,400 26,800 51.562 2.030 128,300 28,800 51.816 2.040 149,700 33,650 52.832 2.080 159,000 35,750 53.848 2.120 160,400 36,000 54.356 2.140 159,500 35,850 54.864 2.160 151,500 34,050 55.880 2.200 124,700 28,000 56.642 2.230 Fracture (a) Plot the data as engineering stress versus engineering strain. (b) Compute the modulus of elasticity. (c) Determine the yield strength at a strain offset of 0.002. (d) Determine the tensile strength of this alloy. (e) What is the approximate ductility, in percent elongation? (f) Compute the modulus of resilience.

Anthony Lovill BE1500 Quiz 10 November 29, 2016 %This function file calculates the maximum number within a given cell %array. function [maxNum]= Quiz_10(a); [m,n]=size(a); i=1; k=1; while i<=m j=1; while j<=n c=class(a{i,j}); if strcmp(c,'double') for t=1:length(a{i,j}) vec=a{i,j}; g(k)=vec(t); k=k+1; end elseif strcmp(c,'cell') if strcmp(c,'double') for t=1:length(a{i,j}) vec=a{i,j}; g(k)=vec(t); k=k+1; end end else end j=j+1; end i=i+1; end i=1; j=2; d=length(g); while j<=d if g(i)>g(j) g(j)=g(i); g(i)=g(j); end j=j+1; i=i+1; end maxNum=g(d); disp(maxNum) >> Q