A Thermos for Liquid Helium. A physicist uses a cylindrical metal can 0.250 m high and 0.090 m in diameter to store liquid helium at 4.22 K; at that temperature the heat of vaporization of helium is 2.09 X 104 J/kg. Completely surrounding the metal can are walls maintained at the temperature of liquid nitrogen, 77.3 K, with vacuum between the can and the surrounding walls. How much helium is lost per hour? The emissivity of the metal can is 0.200. The only heat transfer between the metal can and the surrounding walls is by radiation.

Solution 115P The rate of radiation of heat is given by dQ = A(T 4 T 4) dt 1 2 Here the area of the container is 2 (0.090 m) A = 2( d ) + dh = 2( ) + (0.090 m)(0.250 m) = 0.083 m 2 4 4 Therefore the rate of energy radiation is dQ 2 8 2 4 4 4 2 dt = (0.083 m )(0.200)(5.67 × 10...