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?Finding a Derivative In Exercises 53–78, find the derivative of the function. \(y=\sqrt{e^{2 x}+e^{-2 x}}\)

Calculus: Early Transcendental Functions | 6th Edition | ISBN: 9781285774770 | Authors: Ron Larson ISBN: 9781285774770 141

Solution for problem 67 Chapter 3

Calculus: Early Transcendental Functions | 6th Edition

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Calculus: Early Transcendental Functions | 6th Edition | ISBN: 9781285774770 | Authors: Ron Larson

Calculus: Early Transcendental Functions | 6th Edition

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Problem 67

Finding a Derivative In Exercises 53–78, find the derivative of the function.

\(y=\sqrt{e^{2 x}+e^{-2 x}}\)

Text Transcription:

y=sqrt e^2x+e^-2 x

Step-by-Step Solution:

Step 1 of 5) Figure 15.3 The path of integration in Example 2.

Step 2 of 2

Chapter 3, Problem 67 is Solved
Textbook: Calculus: Early Transcendental Functions
Edition: 6
Author: Ron Larson
ISBN: 9781285774770

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?Finding a Derivative In Exercises 53–78, find the derivative of the function. \(y=\sqrt{e^{2 x}+e^{-2 x}}\)