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?Finding a Derivative In Exercises 53–78, find the derivative of the function. \(y=\frac{1}{b^{2}}\left[\ln (a+b x)+\frac{a}{a+b x}\right]\)

Calculus: Early Transcendental Functions | 6th Edition | ISBN: 9781285774770 | Authors: Ron Larson ISBN: 9781285774770 141

Solution for problem 75 Chapter 3

Calculus: Early Transcendental Functions | 6th Edition

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Calculus: Early Transcendental Functions | 6th Edition | ISBN: 9781285774770 | Authors: Ron Larson

Calculus: Early Transcendental Functions | 6th Edition

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Problem 75

Finding a Derivative In Exercises 53–78, find the derivative of the function.

\(y=\frac{1}{b^{2}}\left[\ln (a+b x)+\frac{a}{a+b x}\right]\)

Text Transcription:

y=1/b^2[ln(a+bx)+a/a+bx]

Step-by-Step Solution:

Step 1 of 5) We use polar coordinates and parametrize S by noting that above the point (r, u) in the plane, the z–coordinate of S is y2 - x2 = r2 sin2 u - r2 cos2 u. A parametrization of S is r(r, u) = (r cos u)i + (r sin u)j + r2(sin2 u - cos2 u)k, 0 … r … 1, 0 … u … 2p. We next compute * F # n ds.

Step 2 of 2

Chapter 3, Problem 75 is Solved
Textbook: Calculus: Early Transcendental Functions
Edition: 6
Author: Ron Larson
ISBN: 9781285774770

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?Finding a Derivative In Exercises 53–78, find the derivative of the function. \(y=\frac{1}{b^{2}}\left[\ln (a+b x)+\frac{a}{a+b x}\right]\)