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Get Full Access to Calculus: Early Transcendental Functions - 6 Edition - Chapter 3 - Problem 75
Get Full Access to Calculus: Early Transcendental Functions - 6 Edition - Chapter 3 - Problem 75

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?Finding a Derivative In Exercises 53–78, find the derivative of the function. $$y=\frac{1}{b^{2}}\left[\ln (a+b x)+\frac{a}{a+b x}\right]$$

ISBN: 9781285774770 141

Solution for problem 75 Chapter 3

Calculus: Early Transcendental Functions | 6th Edition

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Problem 75

Finding a Derivative In Exercises 53–78, find the derivative of the function.

$$y=\frac{1}{b^{2}}\left[\ln (a+b x)+\frac{a}{a+b x}\right]$$

Text Transcription:

y=1/b^2[ln(a+bx)+a/a+bx]

Step-by-Step Solution:

Step 1 of 5) We use polar coordinates and parametrize S by noting that above the point (r, u) in the plane, the z–coordinate of S is y2 - x2 = r2 sin2 u - r2 cos2 u. A parametrization of S is r(r, u) = (r cos u)i + (r sin u)j + r2(sin2 u - cos2 u)k, 0 … r … 1, 0 … u … 2p. We next compute * F # n ds.

Step 2 of 2

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Calculus: Early Transcendental Functions : Exponential and Logarithmic Functions