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Get Full Access to Calculus: Early Transcendental Functions - 6 Edition - Chapter 3 - Problem 76
Get Full Access to Calculus: Early Transcendental Functions - 6 Edition - Chapter 3 - Problem 76

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# ?Finding a Derivative In Exercises 53–78, find the derivative of the function. $$y=\frac{1}{b^{2}}[a+b x-a \ln (a+b x)]$$

ISBN: 9781285774770 141

## Solution for problem 76 Chapter 3

Calculus: Early Transcendental Functions | 6th Edition

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Problem 76

Finding a Derivative In Exercises 53–78, find the derivative of the function.

$$y=\frac{1}{b^{2}}[a+b x-a \ln (a+b x)]$$

Text Transcription:

y=1/b^2[a+bx-a ln (a+b x)]

Step-by-Step Solution:

Step 1 of 5) Figure 15.70 A uniformly expanding vector field and a sphere (Example 2).

Step 2 of 2

##### ISBN: 9781285774770

Calculus: Early Transcendental Functions was written by and is associated to the ISBN: 9781285774770. This textbook survival guide was created for the textbook: Calculus: Early Transcendental Functions, edition: 6. The full step-by-step solution to problem: 76 from chapter: 3 was answered by , our top Calculus solution expert on 11/14/17, 10:53PM. The answer to “?Finding a Derivative In Exercises 53–78, find the derivative of the function.$$y=\frac{1}{b^{2}}[a+b x-a \ln (a+b x)]$$Text Transcription:y=1/b^2[a+bx-a ln (a+b x)]” is broken down into a number of easy to follow steps, and 20 words. This full solution covers the following key subjects: derivative, exercises, Find, function. This expansive textbook survival guide covers 134 chapters, and 10738 solutions. Since the solution to 76 from 3 chapter was answered, more than 237 students have viewed the full step-by-step answer.

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?Finding a Derivative In Exercises 53–78, find the derivative of the function. $$y=\frac{1}{b^{2}}[a+b x-a \ln (a+b x)]$$