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?Finding a Derivative In Exercises 53–78, find the derivative of the function. \(y=-\frac{1}{a x}+\frac{b}{a^{2}} \ln \frac{a+b x}{x}\)

Calculus: Early Transcendental Functions | 6th Edition | ISBN: 9781285774770 | Authors: Ron Larson ISBN: 9781285774770 141

Solution for problem 78 Chapter 3

Calculus: Early Transcendental Functions | 6th Edition

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Calculus: Early Transcendental Functions | 6th Edition | ISBN: 9781285774770 | Authors: Ron Larson

Calculus: Early Transcendental Functions | 6th Edition

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Problem 78

Finding a Derivative In Exercises 53–78, find the derivative of the function.

\(y=-\frac{1}{a x}+\frac{b}{a^{2}} \ln \frac{a+b x}{x}\)

Text Transcription:

y=-1/ax+b/a^2 ln a+bx/x

Step-by-Step Solution:

Step 1 of 5) Figure A.7 Triangles P1QP2 and P1′Q′P2′ are similar, so the ratio of their sides has the same value for any two points on the line. This common value is the line’s slope.

Step 2 of 2

Chapter 3, Problem 78 is Solved
Textbook: Calculus: Early Transcendental Functions
Edition: 6
Author: Ron Larson
ISBN: 9781285774770

The answer to “?Finding a Derivative In Exercises 53–78, find the derivative of the function.\(y=-\frac{1}{a x}+\frac{b}{a^{2}} \ln \frac{a+b x}{x}\)Text Transcription:y=-1/ax+b/a^2 ln a+bx/x” is broken down into a number of easy to follow steps, and 19 words. This full solution covers the following key subjects: derivative, exercises, Find, function. This expansive textbook survival guide covers 134 chapters, and 10738 solutions. Since the solution to 78 from 3 chapter was answered, more than 231 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Calculus: Early Transcendental Functions, edition: 6. Calculus: Early Transcendental Functions was written by and is associated to the ISBN: 9781285774770. The full step-by-step solution to problem: 78 from chapter: 3 was answered by , our top Calculus solution expert on 11/14/17, 10:53PM.

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?Finding a Derivative In Exercises 53–78, find the derivative of the function. \(y=-\frac{1}{a x}+\frac{b}{a^{2}} \ln \frac{a+b x}{x}\)