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Get Full Access to University Physics - 13 Edition - Chapter 18 - Problem 47e
Get Full Access to University Physics - 13 Edition - Chapter 18 - Problem 47e

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# For diatomic carbon dioxide gas (CO2, molar mass 44.0

ISBN: 9780321675460 31

## Solution for problem 47E Chapter 18

University Physics | 13th Edition

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Problem 47E

For diatomic carbon dioxide gas (CO2, molar mass 44.0 g/mol) at T = 300 K, calculate (a) the most probable speed vmp; (b) the average speed vav; (c) the root-mean-square speed rms.

Step-by-Step Solution:

Solution 47E Step 1: Molar mass of CO = 44.0 g/ mol 2 1 mol is having avogadro number of molecules in it. 23 Therefore, 1 mol = N =A.023 × 10 molecules Therefore, Molar mass of CO = 42g / (6.023 × 10 ) = 7.31 × 10 -23g 1 g = 10 kg Therefore, molar mass of CO = 7.31 × 10 -26kg 2

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Step 3 of 4

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For diatomic carbon dioxide gas (CO2, molar mass 44.0