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For diatomic carbon dioxide gas (CO2, molar mass 44.0

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 47E Chapter 18

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 47E

For diatomic carbon dioxide gas (CO2, molar mass 44.0 g/mol) at T = 300 K, calculate (a) the most probable speed vmp; (b) the average speed vav; (c) the root-mean-square speed rms.

Step-by-Step Solution:

Solution 47E Step 1: Molar mass of CO = 44.0 g/ mol 2 1 mol is having avogadro number of molecules in it. 23 Therefore, 1 mol = N =A.023 × 10 molecules Therefore, Molar mass of CO = 42g / (6.023 × 10 ) = 7.31 × 10 -23g 1 g = 10 kg Therefore, molar mass of CO = 7.31 × 10 -26kg 2

Step 2 of 4

Chapter 18, Problem 47E is Solved
Step 3 of 4

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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For diatomic carbon dioxide gas (CO2, molar mass 44.0