You have two identical containers, one containing gas A and the other gas B. The masses of these molecules are mA = 3.34 X 10-27 kg and mB = 5.34 X 10-26 kg. Both gases are under the same pressure and are at 10.0o C. (a) Which molecules (A or B) have greater translational kinetic energy per molecule and rms speeds? (b) Now you want to raise the temperature of only one of these containers so that both gases will have the same rms speed. For which gas should you raise the temperature? (c) At what temperature will you accomplish your goal? (d) Once you have accomplished your goal, which molecules ( A or B ) now have greater average translational kinetic energy per molecule?

Solution 69P Step 1: In this question, We need to find which gas has greater greater translational kinetic energy per molecule and rms speed We need to find temperature of which gas has to be raised such that both gases have same rms Temperature required to be raised such that both same rms And also find which molecule will have greater translational kinetic energy Data given 27 Mass of molecules in container A m = A.34 × 10 kg 26 Mass of molecules in container B m = B.34 × 10 kg Both have same temperature =P Temperature is T = 10.0 C = 273 + 10 C = 283 K