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Zorch, an archenemy of Superman, decides to slow Earth’s

Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli ISBN: 9780130606204 3

Solution for problem 16PE Chapter 10

Physics: Principles with Applications | 6th Edition

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Physics: Principles with Applications | 6th Edition | ISBN: 9780130606204 | Authors: Douglas C. Giancoli

Physics: Principles with Applications | 6th Edition

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Problem 16PE

Zorch, an archenemy of Superman, decides to slow Earth’s rotation to once per 28.0 h by exerting an opposing force at and parallel to the equator. Superman is not immediately concerned, because he knows Zorch can only exert a force of 4.00×107 N (a little greater than a Saturn V rocket’s thrust). How long must Zorch push with this force to accomplish his goal? (This period gives Superman time to devote to other villains.) Explicitly show how you follow the steps found in Problem-Solving Strategy for Rotational Dynamics.

Step-by-Step Solution:

Step-by-step solution Step 1 of 2 Zorch, the archenemy of superman, decided to slow the Earth’s rotation to once per 28 hr instead of 24 hr, and for doing so, it exerts a force parallel to the equator of the earth. As the earth completes its rotation in every 24 hour, In a complete rotation the Earth revolves radians, So that the initial angular velocity of the Earth in radians per sec is, Also when the Zorch will apply the force, the Earth will take an hour to complete its rotation. So the final angular velocity of the Earth in radians per sec will be, Here and are the final as well as initial angular velocity of the Earth respectively. Now as the force is exerted by Zorch is on the median of the Earth, so due to this force a corresponding torque will also act and helps in the deceleration of the Earth’s rotation.

Step 2 of 2

Chapter 10, Problem 16PE is Solved
Textbook: Physics: Principles with Applications
Edition: 6
Author: Douglas C. Giancoli
ISBN: 9780130606204

The answer to “Zorch, an archenemy of Superman, decides to slow Earth’s rotation to once per 28.0 h by exerting an opposing force at and parallel to the equator. Superman is not immediately concerned, because he knows Zorch can only exert a force of 4.00×107 N (a little greater than a Saturn V rocket’s thrust). How long must Zorch push with this force to accomplish his goal? (This period gives Superman time to devote to other villains.) Explicitly show how you follow the steps found in Problem-Solving Strategy for Rotational Dynamics.” is broken down into a number of easy to follow steps, and 88 words. The full step-by-step solution to problem: 16PE from chapter: 10 was answered by , our top Physics solution expert on 03/03/17, 03:53PM. This full solution covers the following key subjects: zorch, superman, Force, long, devote. This expansive textbook survival guide covers 35 chapters, and 3914 solutions. Physics: Principles with Applications was written by and is associated to the ISBN: 9780130606204. Since the solution to 16PE from 10 chapter was answered, more than 460 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Physics: Principles with Applications, edition: 6.

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