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Meteorology. The vapor pressure is the pressure of the
Chapter 18, Problem 88P(choose chapter or problem)
Meteorology. The vapor pressure is the pressure of the vapor phase of a substance when it is in equilibrium with the solid or liquid phase of the substance. The relative humidity is the partial pressure of water vapor in the air divided by the vapor pressure of water at that same temperature, expressed as a percentage. The air is saturated when the humidity is 100%.
(a) The vapor pressure of water at \(20.0^{\circ} \mathrm{C}\) is \(2.34 \times 10^{3}\) Pa. If the air temperature is \(20.0^{\circ} \mathrm{C}\) and the relative humidity is 60%, what is the partial pressure of water vapor in the atmosphere (that is, the pressure due to water vapor alone)?
(b) Under the conditions of part (a), what is the mass of water in \(1.00 \mathrm{~m}^{3}\) of air? (The molar mass of water is 18.0 g/mol. Assume that water vapor can be treated as an ideal gas.)
Questions & Answers
QUESTION:
Meteorology. The vapor pressure is the pressure of the vapor phase of a substance when it is in equilibrium with the solid or liquid phase of the substance. The relative humidity is the partial pressure of water vapor in the air divided by the vapor pressure of water at that same temperature, expressed as a percentage. The air is saturated when the humidity is 100%.
(a) The vapor pressure of water at \(20.0^{\circ} \mathrm{C}\) is \(2.34 \times 10^{3}\) Pa. If the air temperature is \(20.0^{\circ} \mathrm{C}\) and the relative humidity is 60%, what is the partial pressure of water vapor in the atmosphere (that is, the pressure due to water vapor alone)?
(b) Under the conditions of part (a), what is the mass of water in \(1.00 \mathrm{~m}^{3}\) of air? (The molar mass of water is 18.0 g/mol. Assume that water vapor can be treated as an ideal gas.)
ANSWER:Solution to 88P Step 1 0 3 Vapour pressure of water at T=20 C = 2.34 X 10 Pa 0 Air temperature =20 C =293.15K Relative humidity =60% 3 Volume of air=1m Molar mass of water = 18.0 g/mol