Solution: In Exercises 5356, find an equation of the tangent
Chapter 13, Problem 56(choose chapter or problem)
In Exercises 53-56, find an equation of the tangent plane to the surface at the given point.
\(f(x, y)=\sqrt{25-y^{2}}\), (2, 3, 4)
Text Transcription:
f(x, y) = sqrt{25 - y^2
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